voidcomp
23 posts
msg #108324
- Ignore voidcomp |
10/9/2012 4:34:49 PM
Check out the bearish divergence between price and RSI 14 - http://imageshack.us/a/img405/6782/aapldivg.jpg
What would be a decent scan formula to capture this, not only for bearish but bullish also? Thanks.
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mahkoh
1,065 posts
msg #108325
- Ignore mahkoh
modified |
10/9/2012 5:20:50 PM
How about this?
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voidcomp
23 posts
msg #108326
- Ignore voidcomp |
10/9/2012 7:22:55 PM
Thanks for the quick response. If the formula basically says there's a big divergence in linear slope between price and RSI(14) over the past month then yes. I've found that divergences over shorter time frames lead to more whipsaw trades.
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Rock Sexton
111 posts
msg #108327
- Ignore Rock Sexton |
10/9/2012 11:15:44 PM
Mahkoh, do you by chance have the inverse of this filter coded for divergent bottoms?
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mahkoh
1,065 posts
msg #108330
- Ignore mahkoh |
10/10/2012 7:28:07 AM
You could use larger values for MA and "day period" to cover longer timeframes. For rsi you may want to create a custom moving average of rsi(14) and require the slope to be above or below 0, something like
set{x,cma(rsi(14),20)}
20 day slope of x above 0 do not draw 20 day slope of x
For an inverse version simply change "dropped" to "gained" and "below" to "above"
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voidcomp
23 posts
msg #108331
- Ignore voidcomp |
10/10/2012 9:09:23 AM
What's a more simple expression that says:
- the 20 day slope of price is > 0 and the 20 day slope of rsi(14) is < 0 (no moving average smoothing)
- express the difference between price slope and rsi slope
Thanks.
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jackmack
334 posts
msg #112487
- Ignore jackmack
modified |
3/28/2013 8:47:13 AM
mahkoh
Quick question for you - I changed this around by adding below and it looks great BUT how do I get it to kick out only those that triggered in just the last day and not those that have been triggered over the last several days or longer?
set{x,cma(rsi(14),20)}
20 day slope of x above 0 do not draw 20 day slope of x
Thanks
Cheers
Never mind - got it - nice filter
Cheers
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